Problem #72
Difficulty: 20%
Counting Fractions
Solution Language: Java
Problem Statement
Consider the fraction, n/d, where n and d are positive integers. If n<d and HCF(n,d)=1, it is called a reduced proper fraction.
If we list the set of reduced proper fractions for d ≤ 8 in ascending order of size, we get:
1/8, 1/7, 1/6, 1/5, 1/4, 2/7, 1/3, 3/8, 2/5, 3/7, 1/2, 4/7, 3/5, 5/8, 2/3, 5/7, 3/4, 4/5, 5/6, 6/7, 7/8
It can be seen that there are 21 elements in this set.
How many elements would be contained in the set of reduced proper fractions for d ≤ 1,000,000?
Approach
The solution involves:
- Recognizing that the count equals the sum of Euler’s totient function φ(d) for d from 2 to 1,000,000
- For each denominator d, φ(d) counts fractions with that denominator
- Computing φ(d) efficiently for all d using a sieve-like approach
- Summing all φ(d) values